Math, asked by samarthraj0601, 4 months ago

The sum of the digits of a two-digit number is 3. If the digits are reversed, the new number increased by 3 is twice the original number. Then the original number is: (a) 12 (b) 30 (c) 21 (d) none of these.​

Answers

Answered by khanariz2006
0

Answer:

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Answered by VismayaDevashya
0

Answer:

option c) 21

Step-by-step explanation:

Given statements:

  1. Sum of the digits of a two-digit number is 3
  2. New number increased by 3 is twice the original number.

Let the two digits be x and y.

The sum of the two digits is equal to 3 this implies that:

x + y = 3 [Equation 2]

The original number is 10x + y, and reversing the digits would be equal to 10y + x.

So according to second statement,

10y + x + 3 = 2( 10x + y )

10y + x + 3 = 20x + 2y

8y - 19x = -3 [Equation 2]

Sloving Equation 1 and Equation 2 we get the values of x and y as x = 2 and y = 1.

So the original number 10x + y = 10(2) + 1 = 20 + 1 = 21

Option c) 21 is the correct answer.

#SPJ2

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