The sum of the digits of a two digit number is 5.
If the digits are reversed, the number is reduced
by 27. Find the number.
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Step-by-step explanation:
Let the digits of the required no. s be x and y.
So, x+y=5(let this be eqn 1).
The required no. =10x+y
So reversed no. =10y+x
Since on reversing, the no. is reduced by 27,
10y+x-(10x+y) =27
On solving, we'll get 9x-9y=27 or x-y=3(let this be eqn 2)
On solving the 2 equations, we will get
x=4, y=1.
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