Question

The sum of the digits of a two digit number is 5. If the digits are reversed the number is reduced by 27.

Answer 1

Answer:

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Answer 2

• Let one's digit be M and ten's digit be N.

• Original number = 10N + M

» The sum of the digits of a two digit number is 5.

→ M + N = 5

→ M = 5 - N ________ (eq 1)

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» If the digits are reversed the number is reduced by 27.

• Revered number = 10M + N

A.T.Q.

→ 10M + N = 10N + M - 27

→ 10M - M + N - 10N = - 27

→ 9M - 9N = - 27

→ M - N = - 3

→ (5 - N) - N = - 3 [From (eq 1)]

→ 5 - 2N = - 3

→ - 2N = - 8

→ N = 4

Put value of N in (eq 1)

→ M = 5 - 4

→ M = 1

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Number = 10N + M => 10 × 4 + 1

→ 41

________ [ ANSWER ]

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