Question

The sum of the digits of a two digit number is 5. If the digits are

interchanged the sum of the original number & interchanged number

is 55, find the number​

Answer 1

Answer:

let the digit at one's place be x

therefore the digit at ten's place be 5-x

and the no. = 10(5-x) + x

= 50 - 10x + x = 50 - 9x

and the interchanged no.

10x + 5 - x = 9x + 5

according to the question,

50 - 9x + 9x + 5 = 55

55x = 55

x = 1

so,

the digit at one's place = 1

and the digit at ten's place = 5 - x = 5 - 1 = 4

and the no. = 41

Step-by-step explanation:

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