The sum of the digits of a two digit number is 5. If the digits are reversed, the number is reduced by 27. Find the number.
Answers
Answer:
Let the digits be x and y respectively.
Therefore, x + y = 5 --------(1)
Original Number = 10x + y
Reversed Number = 10y + x
10 + y - (10y + x) = 27
10x + y - 10y - x = 27
9x - 9y = 27
9(x - y) = 27
x - y = 3 --------(2)
Adding equation (1) and (2)
2x = 8
x = 4
Substituting value for x in equation (1), we get
4 + y = 5
y = 5 - 4
y = 1
The numbers are 41 and 14.
Question:
The sum of the digits of a two digit number is 5. If the digits are reversed, the number is reduced by 27. Find the number.
To find:
- Number
Given :
- The sum of the digits of a two digit number is 5.
- digits are reversed, the number is reduced by 27.
Let:
- unit place = x
- tens place = y
Answer:
Original number = tens place digit × 10 + unit place digit
.°. Original number = 10y+x
Reversed number = 10x+y
A.T.Q
When digits i.e. x and y are are reversed, the number is reduced by 27.
A.T.Q
Sum of digits =5
Now put value of Y in equation 2
Now put value of x in equation 1
As in question it's asked to find value of number
.°. put value of x and y in this equation:
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And all we are done! ✔
:D