Question

the sum of the digits of a two-digit number is 5 if the digits are reversed the number is reduced by 27 find the number

Answer 1

Hey friend...!! here's your answer
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Let the unit digit = x
ten's digit = y

x + y = 5------1

According to question,

10x + y - 27 = 10y + x
10x - x = 10y - y + 27
9x = 9y + 27
9x - 9y - 27 =0
9( x - y - 3) =0
x - y =3 -----2


By solving equation 1 and 2

x = 5 - y ---------3


Put the value of equation 3 in equation 2
5 - y - y = 3
-2y = -2
y = 1

Put the value of y in equation 3

x = 5 - 1
x = 4

we know that the unit = x and ten's digit = y

So the number formed xy

Put the value of x and y in xy

so we obtained 41.

So that the number is 41

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#Hope its help you dear#
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Answer 2

Step-by-step explanation:

Assume , tens Digit = x and ones digit = y

x + y = 5

x = 5 - y

10y + x = 10x + y - 27

9y - 9x = -27

x - y = 3

5 - y - y = 3

2y = 2

y = 1

x = 5 - 1

x = 4

Number = 10*4+1 = 41