Question

The sum of the digits of a two digit number
is 5. If the digits
are reversed the number
is reduced by 27. Find the number.
​

Answer 1

Answer:

• let x and y be 2 digits so
• x +y= 5
• and if it's reversed it reduced by27
• so 4+1=5 the the 2 digits are 41 the if reverse it ,it will become 14
• then 41 -14 =27
• therefore the number is 41

Answer 2

Answer:

41

Step-by-step explanation:

Given that,

• The sum of the digits of a two digit number is 5.
• If the digits are reversed the number is reduced by 27.

We are asked to calculate the numbers.

Let us assume the two digit number as 10x + y where x and y are its digits. According to the question,

• The sum of the digits of a two digit number is 5. Writing it in the form of an equation,

$\longrightarrow$ x + y = 5

$\longrightarrow$ x = 5 - y __(i)

Also, if the digits are reversed the number is reduced by 27.

$\longrightarrow$ 10y + x = 10x + y - 27

Substitute the value of x in this equation from equation (i).

$\longrightarrow$ 10y + 5 - y = 10(5 - y) + y - 27

$\longrightarrow$ 9y + 5 = 50 - 10y + y - 27

$\longrightarrow$ 9y + 5 = 23 - 9y

$\longrightarrow$ 9y + 9y = 23 - 5

$\longrightarrow$ 18y = 18

$\longrightarrow$ y = 18 ÷ 18

$\longrightarrow$ y = 1

Now, substitute the value of y in the equation 1 to find the value of x.

$\longrightarrow$ x = 5 - y

$\longrightarrow$ x = 5 - 1

$\longrightarrow$ x = 4

Now, we'll calculate the original number.

$\longrightarrow$ Original number = 10x + y

$\longrightarrow$ Original number = 10(4) + 1

$\longrightarrow$ Original number = 40 + 1

$\longrightarrow$ Original number = 41

Therefore, the original number is 41.