The sum of the digits of a two_digit number is 5 . On adding 27 to the number , its digits are reversed . Find the original number.
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no. of two digit=10x+y
x+y=5 (eq.1) multiply by 9
then
10x+y+27=10y+x
9x-9y+27=0
9x-9y=-27 (eq.2)
adding eq2 and eq1,we get,
9x-9y=-27
9x+9y=45
18x=18
x=1
y=4
put the value of x and y
then no. is 14.
x+y=5 (eq.1) multiply by 9
then
10x+y+27=10y+x
9x-9y+27=0
9x-9y=-27 (eq.2)
adding eq2 and eq1,we get,
9x-9y=-27
9x+9y=45
18x=18
x=1
y=4
put the value of x and y
then no. is 14.
ridhima4:
thanks
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