the sum of the digits of a two-digit number is 5. on adding 27 to the no. , it's digits are reversed. find the original no.
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The original number is 14
zofia1:
Plz explain in step by step answer and then get 14
Answered by
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Let the two digit no be 10x+y where x = ten's digit no and y = one's digit no
Then acc to ques
x + y = 5 ........1
10x + y + 27 = 10y + x
9x - 9y = -27 ........2
From 1
y = 5 - x ........3
Substituting 3 in 2
9x - 9(5-x) = -27
-45 + 18x = -27
18x = 18
x = 1
Then y = 5 - x
y = 5 - 1
y = 4
So the no is 14 (10x + y = 10(1) + 4 = 14)
:) Hope this Helps !!!
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Then acc to ques
x + y = 5 ........1
10x + y + 27 = 10y + x
9x - 9y = -27 ........2
From 1
y = 5 - x ........3
Substituting 3 in 2
9x - 9(5-x) = -27
-45 + 18x = -27
18x = 18
x = 1
Then y = 5 - x
y = 5 - 1
y = 4
So the no is 14 (10x + y = 10(1) + 4 = 14)
:) Hope this Helps !!!
PLS SUPPORT SYRIANS
LOOK AT THEIR DIFFICULTIES IN GOOGLE
LETS SUPPORT SYRIANS
LET THE SUPPORT OF INDIA START FROM US
add the above statement in ur ques and ans
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