Question

the sum of the digits of a two digit number is 5 . the number formed by reversing the digits is 9 less tham the orignal number .find the orignal number-​

Answer 1

Answer:

x + y = 5 . (i)

IOy+x-9=10x+y

-9x+9y=9

-x+y=1 (2)

2 y=6,y=3

x+y=5. Ans

x +3=5

x = 2. ..... Ans

Answer 2

Answer:

let the digit at unit place be X

then, the digit at the tens place=5-x

original number=10(5-x)+1*X

=50-10x+X

=50-9x

digit formed by reversing its digit

=10*X+1(5-x)

=10x+5-x

=9x+5

A/Q

50-9x-9=9x+5

=41-9x=9x+5

=41-5=9x+9x

=36=18x

=2=X

original number=50-9x

=50-9*2

=50-18=32

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