Question

the sum of the digits of a two digit number is 5. the number formed by reversing the digits is less then nine than the original number find the original number

Answer 1

Take the no xy.
this means 10x+y( expansion form).

reverse the digits then the no is yx
yx= 10y+ x
the difference = 9x-9y
in the question the difference is given
9(x-y) = 9
so x-y =1, .....1
sum of the digits is x+y = 5 .....2

from the 2 statements x=3, y=2
finally the original no is 32