The sum of the digits of a two- digit number is 5. The number obtained by reversing the order of digit diminished the original number by 9. Find the number.
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Answered by
15
Answer:let digit at unit place be x and at tens be y so no formed = 10y+x
also x+y =5
now when digits are reversed digit at unit place is y so no formed
=10x+y now
10y+x-10x+y=9 so
9y-9x=9.
Y-x=9 also
y+x=5 on adding
Y=x= 2 so
no is 32
hope it helps u mate.....
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also x+y =5
now when digits are reversed digit at unit place is y so no formed
=10x+y now
10y+x-10x+y=9 so
9y-9x=9.
Y-x=9 also
y+x=5 on adding
Y=x= 2 so
no is 32
hope it helps u mate.....
pls mark me brainliest
kaushalsingh122:
thanks
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Answered by
1
Answer:
why you answer give 32 .
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