Question

the sum of the digits of a two-digit number is 6. if the digits are reversed, the new number will be 36 greater than the original number. find the number

Answer 1

Let the ones digit be x
And tens digits be y so the no is 10x + y and A. T. Q
x+y =6 and 10y+x =10x +y +36
9y - 9x = 36 so y-x =4 so from this y = 5and x=1 so the no is 15 sorry for wrong answers

Answer 2

Answer :

[ Given ]

The sum of two digit = 10

Then suppose first digit = x

And second digit = y

Then the equation found x + y = 10

Now interchanging the number is decreased by 36

(10x + y) = (10y - x) -36

Then 10x - x + y - 10y = -36

9x - 9y = -36

Then all are divided by 9

So second equation found => x - y = -4

Add first and second equation

x + y = 10

+ x - y = 4

=> 2x = 6

then x = 3

Now First equation = 3 + y = 10

y = 10-3 = 7

y =7

Then original number = (10x + y)

10 x 3 + 7

=> 37 Answer √√