Question

The sum of the digits of a two digit number is 7 if 2 is subtracted from the number formed by interchanging the digits the result is double the original number find the original number

Answer 1

LET THE UNIT BE DIGIT Y AND TENS DIGIT BE 10x

The original number be-(10x-y)

After reversing the number (10y-x)

10(x+y) + 10(y+x) =110

10(x+y)=110

11(x+y) + 11(y+x) =110

11(x+y) =110

x+y = 110÷11

x+y = 10

(10x+y) = x+y(10)

(10x+y) = 5+4 (10)

10(10-y) + y = 4+50+10

10(10-y) + y = 64

100y +y = 64

99y = 64

now from there you have to try for better learning.

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help.

x=6

y=4