Question

The sum of the digits of a two digit number is 7 if the digits are reversed

Answer 1

Step-by-step explanation:

Take the no xy. this means 10x+y( expansion form).

reverse the digits then the no is yx

yx= 10y+ x

the difference = 9x-9y

in the question the difference is given

9(x-y) = 9

so x-y =1,

sum of the digits is x+y = 7

from the 2 statement s x=4, y=3

finally the no is 43