Question

The sum of the digits of a two digit number is 7. If the number formed by reversing the digits is

less than the original number by 27, find the original number.

Answer 1

Let the number be 10x+y

also given that x+y = 7

so, x = 7-y ---(1)

also, 10y + x = 10x+y +45

9y = 45 +9x

y = 5+x ----(2)

putting the value of (1) in (2)

so, y = 5+ ( 7-y)

=> y = 5 + 7 - y

=> y +y = 12

=> 2y = 12

=> y = 6

so, x = 7-y = 7-6

=> x = 1

Hence for original number we must put value of x and y that is 1 and 6 respectively... Therefore 10x+y=10×1+6=16

so, the number is 16.

Hope that helps you!!! ☺️☺️☺️