The sum of the digits of a two digit number is 7. If the number formed by reversing the digits is
less than the original number by 27, find the original number.
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Let the number be 10x+y
also given that x+y = 7
so, x = 7-y ---(1)
also, 10y + x = 10x+y +45
9y = 45 +9x
y = 5+x ----(2)
putting the value of (1) in (2)
so, y = 5+ ( 7-y)
=> y = 5 + 7 - y
=> y +y = 12
=> 2y = 12
=> y = 6
so, x = 7-y = 7-6
=> x = 1
Hence for original number we must put value of x and y that is 1 and 6 respectively... Therefore 10x+y=10×1+6=16
so, the number is 16.
Hope that helps you!!! ☺️☺️☺️
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