The sum of the digits of a two digit number is 7.if the number formed by reversing the digits is less than the original number by 27, find the original number.
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Step-by-step explanation:
ake the no xy. this means 10x+y( expansion form).
reverse the digits then the no is yx
yx= 10y+ x
the difference = 9x-9y
in the question the difference is given
9(x-y) = 9
so x-y =1,
sum of the digits is x+y = 7
from the 2 statement s x=4, y=3
finally the no is 43
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