The sum of the digits of a two digit number is 7. If the number formed by reversing the digits is less than the original number by 27, find the original number.??
Answers
Answer:
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Step-by-step explanation:
Let the units digit of the original number be x.
Then the tens digit of the original number be 7 - x
Then the number formed = 10(7 - x) + x × 1
= 70 - 10x + x = 70 - 9x
On reversing the digits, the number formed
= 10 × x + (7 - x) × 1
= 10x + 7 - x = 9x + 7
According to the question,
New number = original number - 27
⇒ 9x + 7 = 70 - 9x - 27
⇒ 9x + 7 = 43 - 9x
⇒ 9x + 9x = 43 – 7
⇒ 18x = 36
⇒ x = 36/18
⇒ x = 2
Therefore, 7 - x
= 7 - 2
= 5
The original number is 52
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Answer:
Step-by-step explanation:
unit digit = x.
tens digit 7 - x
no. formed = 10(7 - x) + x × 1
70 - 10x + x = 70 - 9x
10 × x + (7 - x) × 1
10x + 7 - x = 9x + 7
9x + 7 = 70 - 9x - 27
9x + 7 = 43 - 9x
9x + 9x = 43 – 7
18x = 36
x = 36/18
⇒ x = 2
Therefore, 7 - x
= 7 - 2
= 5
original no. is 52