Math, asked by kishan7884, 10 months ago

The sum of the digits of a two digit number is 7. If the number formed by reversing the digits is less than the original number by 27, find the original number.??

Answers

Answered by Anonymous
8

Answer:

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Step-by-step explanation:

Let the units digit of the original number be x.

Then the tens digit of the original number be 7 - x

Then the number formed = 10(7 - x) + x × 1

= 70 - 10x + x = 70 - 9x

On reversing the digits, the number formed

= 10 × x + (7 - x) × 1

= 10x + 7 - x = 9x + 7

According to the question,

New number = original number - 27

⇒ 9x + 7 = 70 - 9x - 27

⇒ 9x + 7 = 43 - 9x

⇒ 9x + 9x = 43 – 7

⇒ 18x = 36

⇒ x = 36/18

⇒ x = 2

Therefore, 7 - x

= 7 - 2

= 5

The original number is 52

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Answered by sonabrainly
0

Answer:

Step-by-step explanation:

unit digit =  x.

tens digit  7 - x

no. formed  = 10(7 - x) + x × 1

70 - 10x + x = 70 - 9x

10 × x + (7 - x) × 1

10x + 7 - x = 9x + 7

9x + 7 = 70 - 9x - 27

9x + 7 = 43 - 9x

9x + 9x = 43 – 7

18x = 36

x = 36/18

⇒ x = 2

Therefore, 7 - x

= 7 - 2

= 5

original no. is 52

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