Question

the sum of the digits of a two digit number is 7. if the digits are reversed the new number is 3 less than 4 times the original number. find the original number ​

Answer 1

Let the digits be x and y... and so, the original number be 10x + y ( since x in tenth place and y in unit place)

so, given : sum of the digits = x + y = 7 ---------> (A)

reversing the digits means y in tenth place and x in unit place.. so, the reversed number be 10y + x

given: reversed number is decreased by 2 = twice original number

so, 10y + x - 2 = 2(10x + y)

simplifying : 19x - 8y = -2 ------------> (B)

solving 2 eqns (A) & (B) ,

we get x = 2 and y = 5

so the original number is 10x + y = 10(2) + 5 = 25

& the reversed number is 10y + x = 10(5) + 2 = 52

& the reversed number 52 when decreased by 2 is 50 which is twice the original number 25

Ans: the original number is 25

Answer 2

Answer:

Step-by-step explanation:

I guess your question is wrong..because this will be the equation.. but this won't bring a whole no. It's giving fraction as the answer which is not possible.. so plzz check your question once dear...