the sum of the digits of a two-digit number is 7 if the digits are reversed the new number will be two more than twice the orginal number find the number
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hey your answer is as follows
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Step-by-step explanation:
so let the required two digit number be 10x+y
wherein digit at tens place is x and that of units ie onws place is y
so this reversed number is 10y+x
according to the first condition
x+y=7
so x=7-y (1)
according to the second condition
10y+x=2(10x+y)+2
=20x+2y+2
ie 8y=19x+2 (2)
substitute value of x from (1) in (2)
we get 8y=19(7-y)+2
=133-19y+2
=135-19y
so thus 27y=135
hence y=5
substitute value of y in any of two equations
we get x=2
so our required two digit number=10x+y
=(10×2)+5
=20+5
=25
thus our required two digit number is 25
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