Question

the sum of the digits of a two-digit number is 7 if the number formed by the reversing the digit is more than the original number by 27 and the original number

Answer 1

let original no be XY
x+Y =7

YX = XY +27

Y0 + X= X0 + Y + 27
Y0 + 7-Y=( 7-Y)10 + Y +27

9Y + 7 = 70 - 10 Y + Y +27
18Y= 90
Y= 5

X= 2

SO NO IS 25