the sum of the digits of a two-digit number is 7 if the digits are reversed the new number increased by 3 = 4 original number find the original number
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Answer: 16
Step-by-step explanation:
Let the one's digit be b and ten's digit be a. Then the number is 10a+b
Given the sum of digits = 7
a+b=7 -----(1)
If the digit is reverses, the number will be 10b+a.
Then 10b+a+3=4(10a+b)
⇒10b + a + 3 = 40a + 4b
⇒39a - 6b = 3
⇒13a-2b=1 ------(2)
(1) x 2 ---->
2a + 2b = 14 ------(3)
(2) + (3) ---->
15a=15
a=1
a+b=7
So b = 6
So the original number is 16
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Very useful solution
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