The sum of the digits of a two digit number is 7. On reversing the digits, the new number becomes 28 more than twice the unit’s digit of the original number. Find the original number.
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Answer:
43
Step-by-step explanation:
The sum of the digits of a two digit number is 7.on reversing the digits, the new number becomes 28 more than twice the unit's digit of the original number.
Let the unit digit be x
And other=(7-x)
ATQ.
10x+(7-x)-28=2x
10x+7-x=2x+28
9x+7=2x+28
9x-2x=28-7
7x=21
X=21/7=3
Therefore, the original no. =10(7-x)+x
=10(7-3)+3
=10×4+3
=43
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