The sum of the digits of a two-digit number is 7. The number obtaind by interaching the digits exceeds the original number by 27.Find the number.
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Answer:
the no. is XY
X+Y = 7~~~~{eq1}
YX =XY+27
10y+x=10x+y+27
9y=9x+27
y=x+3
x-y=3~~~~{eq2}
Step-by-step explanation:
x+y=7
x-y=3
______
2x=10
x=10/2
x=5
x-y=3
5-y=3
y=5-3
y=2
the no. is XY=52
sana143143:
excuse I did a small mis I m really fr that plzz check it once y=x+3 then x-y=-3 so plzz be careful
excuse me I did a small mistake I am really sorry for that plzz check it once y=x+3 then x-y=-3
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