The sum of the digits of a two-digit number is 7. The number formed by reversing the digits is 45 more than
the original number find the original number.
... of the digite of a two-digit number is 9 Tf 9 is added to the number the digits interchange their
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let the no. be =x
and other no. be=9-x
the no. is 10x+9-x
according to question we should add 9
10x+9-x+9=10(9-x)+x
9x+18=90-9x
18x=90-18
x=72÷18
x=4
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