Math, asked by fatema7480, 10 months ago

the sum of the digits of a two digit number is 7. the number obtained by interchanging the digits exceeds the orignal number by 27. find the number​

Answers

Answered by sameer1804
1

let the first digit of original number be 10x

and the second digit of original number 7-x

after interchanging the digits

the first digit of the new number is equal to 70 - 10 x

the second digit of the new number is equal to x

new no.=70-10x+x

=70-9x

original no.=20x+7-x

=19x+7

according to question

70-9x-19x-7=27

63-28x=27

63-27=28x

36=28x

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following

Answered by dasrashmita1234
0

Answer:

522

Step-by-step explanation:

let ,

the number in one's place be x

the number in ten's place be 10 (7-x)

so , the 2 digit no. becomes = 10 (7-x) + x

I.e, = 70-10x + x

= 70 - 9x

A.T.Q (Acc. to the question),

=> 70- 9x = (10x + 7-x) + 27

=> 70 - 9x = 10x + 7- x + 27

=>70-34 = 9x+ 9x

=> 36=18x

=>x=2

so the two digit number =70-9x

= 70 - 9(2)

= 52.

HOPE IT HELPS YOU

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