the sum of the digits of a two digit number is 7. the number obtained by interchanging the digits exceeds the orignal number by 27. find the number
Answers
let the first digit of original number be 10x
and the second digit of original number 7-x
after interchanging the digits
the first digit of the new number is equal to 70 - 10 x
the second digit of the new number is equal to x
new no.=70-10x+x
=70-9x
original no.=20x+7-x
=19x+7
according to question
70-9x-19x-7=27
63-28x=27
63-27=28x
36=28x
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following
Answer:
522
Step-by-step explanation:
let ,
the number in one's place be x
the number in ten's place be 10 (7-x)
so , the 2 digit no. becomes = 10 (7-x) + x
I.e, = 70-10x + x
= 70 - 9x
A.T.Q (Acc. to the question),
=> 70- 9x = (10x + 7-x) + 27
=> 70 - 9x = 10x + 7- x + 27
=>70-34 = 9x+ 9x
=> 36=18x
=>x=2
so the two digit number =70-9x
= 70 - 9(2)
= 52.