Question

The sum of the digits of a two digit number is 7. The number obtained by interchanging the digits exceeds the original number by 27. Find the number ​

Answer 1

Answer:

let digit at ones place = x and  

digit at tens place = y

So, the number will be 10y + x

x + y = 7 .... (1)

Reverse digit will be represented as, 10x + y

So,

( 10x + y ) - ( 10y - x ) = 27

9x - 9y = 27

x - y = 3 .... (2)

Adding equation (1) and (2)

2x = 10

x = 5

Substituting in equation (1)

y = 7 - 5

=2

Thus, the number will be 25.

Hope it helps you!!

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