The sum of the digits of a two-digit number is 7. The number obtained by interchanging the digits exceeds the original number by 27. Find the number
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Let xy be a two-digit number such that
x+y=7
yx=xy+27
x+y=7
10y+x=10x+y+27
x+y=7
-9x+9y=27
x+y=7
x-y=-3
x=2
y=5
The number is 25.
xy+27=yx
25+27=52
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