The sum of the digits of a two digit number is 7. The number formed by reversing the digits is 45 more than the original number . What is the original number.
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Lets say that the original number is represented by 10x + y ; where "x" is the digit at ten's place and "y" is the digit at one's place.
As per the condition in the question, we can write the following equation:
10y + x = 45 + 10x + y
Solving this, we get y = x + 5 ------------ (i)
We have also been given in the question that the sum of the two digits is 7; which means x + y = 7
Putting the value from (i) into this we get x = 1 and hence y = 6
Hence the original number will be 16
As per the condition in the question, we can write the following equation:
10y + x = 45 + 10x + y
Solving this, we get y = x + 5 ------------ (i)
We have also been given in the question that the sum of the two digits is 7; which means x + y = 7
Putting the value from (i) into this we get x = 1 and hence y = 6
Hence the original number will be 16
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