Question

The sum of the digits of a two digit number is 7 the number obtained by interchanging the digit exceeds the orignal number by 27 find the number

Answer 1

Answer:

Step-by-step explanation:

Let the one's place digit = x

∴ ten's place digit = 7-x

Number = 10×(7-x)+1×x

= 70-10x+x

= 70-9x

On interchanging the digits, number becomes= 10×x+1×(7-x)

= 9x+7

ATQ

9x+7-(70-9x)=27

9x+7-70+9x=27

18x-63=27

18x = 27+63

18x = 90

 x = 5

hence one's place digit = 5

and ten's place digit = 7 - 5 = 2

therefore the number = 10×2+1×5

= 25

Hope this helps you!:)