The sum of the digits of a two digit number is 7.when the number subtracted to the number formed by reversing the digits give 27.find the number
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Let the unit digit be x and tens place to so number be 10y+x
X+y=7.........(1)
And
10x+y-10y-x=27
9x-9y=27
9 (x-y)=27
X-y=3........(2)
By adding equation 1&2
We get
X+y+x-y=7+3
2x=10
X=5
From equation (2)
Put the value of x
X-y=3
5-y=3
5-3=y
Y= 2
So required number be
10×2+5=25
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