Math, asked by emarraghu13, 10 hours ago

The sum of the digits of a two-digit number is 7. When the digits of this number are interchanged, the new number formed is two more than twice the original number. Let’s find the original number.

Let the ones digit of the original two-digit number be x. Since the sum of the two digits is 7, its tens digit can be expressed in terms of x as

Answers

Answered by adel984984
1

Answer:

25

Step-by-step explanation:

Let the ones's digit =x.

So, sum of the digits =7

Tens's digit =7−x

Original no. =10(7−x)+x=70−10x+x=70−9x

Reversed no. =10x+7−x=9x+7

2(orig no) = reversed no. −2

2(70−9x)=9x+7−2

140−18x=9x+5

27x=135

x=5

Ten's digit =7−5=2

No. =25

Answered by anythingcreative9234
0

Answer:

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  2. i67ggr45gv
  3. h6ujv7hjn

Step-by-step explanation:

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