Question

- The sum of the digits of a two-digit number is 7the number obtained by reversing the order 27 less than the original number. ,find the original number
दशम ऑफ डिजिट्स आफ ए टू डिजिट नंबर इज द व्हाट इज द नंबर ऑफ टेन बाय रिवर्सिंग ऑर्डर 27 लेस देन द ओरिजिनल नंबर फाइंड द ओरिजिनल नंबर ​

Answer 1

Answer:

We get original number as 52.

Step-by-step explanation:

As it is a two-digit number, Let us assume the digit at ten's place to be x and one's place to be y.

Therefore, the original no. will be 10x+y.

According to the question,

Sum of the digits is 7;

∴ x + y=7                     -(1)

No. obtained by reversing the digits will be 10y+x

According to the question,

The number obtained by reversing the digits is 27 less than the original number;

10y+x=10x+y-27

9y - 9x= -27

-9(x-y)= -27

x - y=(-27/-9)

∴x - y=3                       -(2)

Now we have equations (1) and (2).

Firstly Add (1) and (2)

  x + y= 7

+  x - y= 3

_________

2x=10

∴ x=5

Now subtract (2) from (1).

 x + y= 7

-(x - y)= -3

_________

2y=4

∴y=2

Putting values of x and y in original number 10x+y;

We get original number as 52.