The sum of the digits of a two digit number is 8 and the difference between the number and that formed by neversing the digits is 18. Find the number.
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Let the two digit number be 10a+b
ATQ
a+b= 8 ...(1)
10a+b-(10b+a) = 18
=> 10a+b-10b-a = 18
=> 9a -9b = 18
=> a-b = 2 ...(2)
Adding eqn (1)&(2)
2a = 10
=> a = 5
& b = 3
=> required number is
10a+b =53
Hope it helps
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