Question

The sum of the digits of a two-digit number is 8 and the difference
between the number and the number obtained by reversing the digits is
18.​

Answer 1

Answer:

53

Step-by-step explanation:

let the number in tens place be x

let the number in unit place be y

the number will be 10x + y

the numbers when interchange will be 10y + x

sum of the numbers is 8

x + y = 8 equ (1)

difference between the number and number obtained by reversing digits is 18

10x + y - (10y + x) = 18

10 x + y - 10y - x = 18

9x - 9y = 18

9(x - y) = 18

x - y = 18/9 = 2

x - y = 2 equ (2)

adding equ (1) and (2)

2x = 10

x = 10/2 = 5

substitute x = 5 in equ (1)

x + y = 8

5 + y = 8

y = 8 - 5 = 3

the required number is

= 10x + y

= 10(5) + 3

= 50 + 3

= 53

therefore the required number is 53

hope you get your answer

Answer 2

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