Question

The sum of the digits of a two digit number is 8
and the difference between the number and that
formed by reversing the digits is 18. Find the
number.​

Answer 1

✬ Number = 53 ✬

Step-by-step explanation:

Given:

• Sum of digits of two digit number is 8.
• Difference between original and reversed number is 18.

To Find:

• What is the number ?

Solution: Let the tens digit be x and unit digit be y. Therefore, Number is 10x + y

➟ Tens + Unit = 8

➟ x + y = 8

➟ x = 8 – y.....(1)

[ After reversing the digits ]

• Reversed number = 10y + x

A/q

• Difference between original and reversed number is 18.

$\implies{\rm }$ (10x + y) – (10y + x) = 18

$\implies{\rm }$ 10x + y – 10y – x = 18

$\implies{\rm }$ 9x – 9y = 18

$\implies{\rm }$ 9(x – y) = 18

$\implies{\rm }$ (8 – y) – y = 18/9

$\implies{\rm }$ 8 – 2y = 2

$\implies{\rm }$ 8 – 2 = 2y

$\implies{\rm }$ 6 = 2y

$\implies{\rm }$ 3 = y

So, Digits are

➙ Unit digit is y = 3

➙ Tens digit is x = 8 – 3 = 5

Hence, the number is 10x + y = 10(5) + 3 = 53

Answer 2

Answer:35

Step-by-step explanation:

3+5=8.(sum of individual digits)

53-35=18. (Difference between the number and it's reversed number)