the sum of the digits of a two digit number is 8 and the difference between the number and that formed by reversing the digit is 18. find the number
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x+y=8
10x+y-10y+x=18
9x-9y=18
x-y=2
x+y=8
_______
2x=10
x=5
Putting the valur of x in eq.1
x+y=8
5+y=8
y=3
The number is 10x+y=10×5+3=53.
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10x+y-10y+x=18
9x-9y=18
x-y=2
x+y=8
_______
2x=10
x=5
Putting the valur of x in eq.1
x+y=8
5+y=8
y=3
The number is 10x+y=10×5+3=53.
Hope you liked my answer.
Please mark it as brainliest
sonivaishu58:
Thnx
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2
Here is ur answer...
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