The sum of the digits of a two digit number is 8 . If 36 is added to the number ,the digits interchange their places. Find the numbers.
Answers
Let us assume x and y are the two digits of the number
Therefore, two-digit number is = 10x + y and the reversed number is 10y + x
Given:
x + y = 8
x = 8 – y --------------1
Also given:
10x + y + 36 = 10y + x
9y – 9x = 36
y – x = 4 --------------2
Substitute the value of x from eqn 1 in eqn 2
y – (8 – y) = 4
2y – 8 = 4
2y = 12
y = 6
Therefore, x = 8 – y = 8 – 6 = 2
Therefore, two-digit number = 10x + y = (10 * 2) + 6 = 26
and the reversed number = 10y + x = (10 * 6) + 2 = 62
Let us assume x and y are the two digits of the number
Therefore, two-digit number is = 10x + y and the reversed number is 10y + x
Given:
x + y = 8
x = 8 – y --------------1
Also given:
10x + y + 36 = 10y + x
9y – 9x = 36
y – x = 4 --------------2
Substitute the value of x from eqn 1 in eqn 2
y – (8 – y) = 4
2y – 8 = 4
2y = 12
y = 6
Therefore, x = 8 – y = 8 – 6 = 2
Therefore, two-digit number = 10x + y = (10 * 2) + 6 = 26
and the reversed number = 10y + x = (10 * 6) + 2 = 62