Question

the sum of the digits of a two-digit number is 8. if its reversed , the new number so formed is increased by 18 . find the number. please ans with full explanation do not copy from google please ans fast

Answer 1

Answer:

It is given that sum of the digits,that is x and y, is 8. Therefore we can state, x+y = 8. When we reverse (xy) it becomes (yx), in expanded form it can be written as (10y + x). Again it is given that difference between the two numbers is 18.

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Answer 2

Let the digits in tens place be x and the digits in units place be y.

Therefore, the original two digit number is 10x + y.

Given that Sum of digits of a two digit number is 8.

= > x + y = 8 ------- (1)

Given that The new number increases by 18, when the digits are reversed.

= > 10y + x = 10x + y + 18

= > 10y - y = 10x - x + 18

= > 9y = 9x + 18

= > 9y - 9x = 18

= > y - x = 2

= > x - y = -2 ----- (2)

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On solving (1) & (2), we get

= > x + y = 8

= > x - y = -2

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2x = 6

x = 3.

Substitute x = 3 in (1), we get

= > x + y = 8

= > 3 + y = 8

= > y = 8 - 3

= > y = 5.

So,

= > 10x + y

= > 10(3) + 5

= > 35.

Therefore, the original number = 35.

Hope this helps!

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