The sum of the digits of a two digit number is 8. If its digits are reversed, the new number so formed is increased by 18. What is the number ?
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Let us assume, x and y are the two digits of a two-digit number
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x + y = 8 -----------1
Also given:
10y + x = 10x + y + 18
9y - 9x = 18
y - x = 2 ----------2
Adding equation 1 and equation 2
2y =10
y = 5
Therefore, x = 8 - y = 8 - 5 = 3
Therefore, the two-digit number = 10x + y = 10*3 + 5 = 35
Therefore, the two-digit number = 10x + y and reversed number = 10y + x
Given:
x + y = 8 -----------1
Also given:
10y + x = 10x + y + 18
9y - 9x = 18
y - x = 2 ----------2
Adding equation 1 and equation 2
2y =10
y = 5
Therefore, x = 8 - y = 8 - 5 = 3
Therefore, the two-digit number = 10x + y = 10*3 + 5 = 35
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