Question

the sum of the digits of a two-digit number is 8 if the digits are interchanged the number obtained exceeds the original number by 36 find the number. pls help me...​

Answer 1

Answer:

Step-by-step explanation:

let two digit no. be ab

then sum of digits=8

=a+10b=8

sum of digits when reversed

=b+10a=36

solving the equation we get ans

Answer 2

Answer:

Let's take the number be XY where X is in ten's place and Y is in unit's place So it can also be written as 10(X)+Y =>10X+Y. Sum of digits of the two digit number is 8 => X+Y=8.

If digits are interchanged then Y is in ten's place and X is in unit place =>10(Y)+X .

Difference between new number and old number is given 36 =>10Y+X-(10X+Y) = 36

=>9(Y-X)=36 => Y-X =4. Hence X+Y =8 and Y-X =4 add both these equations =>2Y =12 => Y =6 and X =2 The number is 2(10)+6 => 26. Hope it helps you.