Question

the sum of the digits of a two digit number is 8.if the digits are reversed the new number increases by 18.find the number​

Answer 1

Answer:750×6

5200

Step-by-step explanation:

Answer 2

Answer:

$\text{Let the two digit number be 10a + b}</p><p>$

$\text{Let the number obtained on reversing the digits be 10b + a}</p><p>$

$\text{sum of digits = a + b = 8}$

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ATQ

$10a + b - (10b + a) = 18$

$9( a - b) = 18$

$a - b = 2$

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$\text{Putting the two equations</p><p>together,we get}$

$a + b = 8$

a - b = 2. [by adding]

—————

2a = 10

a = 5.

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$\text{Putting the value in the equation,we get}$

5 + b = 8

b = 3.

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$\text{Hence<strong> </strong><strong>,</strong><strong>the</strong><strong> </strong><strong>n</strong><strong>umber</strong><strong> </strong><strong>is</strong><strong> </strong><strong>1</strong><strong>0</strong><strong>a</strong><strong> </strong><strong>+</strong><strong> </strong><strong>b</strong>}$

$\Rightarrow (10 × 5) + 3 = 53$

$\mathfrak{Hope\:it\: helps\:you}$