Question

The sum of the digits of a two-digit number is 8. If the number formed by reversing the digits is less then the original number by 18. Find the number.

Answer 1

Answer:

answer will be 63

Step-by-step explanation:

let the no. is xy

we can write xy = 10×x + y

also given x+y =8.......................................(1)

now according to the question yx-xy =18

⇒(10y+x)-(10x+y) =18

⇒9y-9x=18

·⇒y-x = 8...............................................(2)

from 1 and 2 we get y=13 and x=5

no. will be 10×6+3 =63

Answer 2

AnSwEr:-

The correct answer of the question is 18.

Explanation:-

Given that -

sum of the digits,that is x and y, is 8.

Therefore,

we can state, x+y = 8.

When we reverse (xy) it becomes (yx), in expanded form it can be written as (10y + x).

Again-

it is given that difference between the two numbers is 18.

So the final answer is 18..

Hope its helpful for u ☘️

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