Question

The sum of the digits of a two digit number is 8. If the digits are reversed, the new number is 18 . (in detail)​

Answer 1

Answer:

ANSWER

Let x be the digit at unit’s place and y be the digit at ten’s place.

Since y is at ten’s place, then the number formed is 10y+x.

By reversing the digits, it becomes 10x+y.

As the difference of the numbers is 18, so,

(10y+x)−(10x+y)=18

9(y−x)=18

y−x=2 .... (1)

As the sum of digits is 8, so,

x+y=8 .... (2)

On adding equations (1) and (2), we get

2y=10⇒y=5

Putting this in (2), we get x=8−5=3

x=3,y=5

Hence, number =10y+x=10×5+3=53.

Step-by-step explanation:

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Answer 2

Answer:

suppose two digits are x and y

then the 2digit number is= 10x+y

when the digits are reversed the new number is= 10y+x

equation 1

x+y=8

equation 2

10y+x = 18

now solving equation 1 and 2 we have

x= 10/9

y= 62/9