Question

the sum of the digits of a two digit number is 8 if the number formed by reversing the digits is less than the original number by 18 find the original number​

Answer 1

Answer:

Step-by-step explanation:

let the unit digit be x

So tense digit (8-x)

Number =10 (8-x)+x=80-10x+x=80 -9x

now interchangeable digit we got

number =10x+8-x=9x+8

according to question

9x+8+18=80 -9x

or

9x+9x=80-26

or

18x=54

or

x=3

number = 80-9x=80-9×3=80-27=53

Answer 2

Answer:

let number be 10x+y

x+y = 8 {1}

10y+x = 10x+y -18

9y-9x+18=0

÷ equation by 9

y- x+2=0{2}

from 1st equation x= 8-y

put this in second equation

y- 8+y+2=0

2y-6=0

y=3

so x= 5

number is = 53