Math, asked by rajyuvi9, 1 year ago

the sum of the digits of a two digit number is 8. The digit in the unit place is 1 more than six times the digit in the tens place. Find the number

Answers

Answered by ammu7771
42

Answer:

17

Step-by-step explanation:

x+y=8. 1.

y= 1+6x. 2.

put y = 1+6x in 1 .

x + 1+6x =8

7x +1 =8

7x=7

x=1

substitute value of x in 2..

y= 1+6*1

y= 7

no. xy = 17

Answered by rajkumararya712
3

Answer:

17  

Step-by-step explanation:

 x+y=8. 1.

y= 1+6x. 2.

put y = 1+6x in 1 .

x + 1+6x =8

7x +1 =8

7x=7

x=1

substitute value of x in 2..

y= 1+6*1

y= 7

no. xy = 17

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