The sum of the digits of a two digit number is 8. The number formed on reversing the
order of the digits is 36 more than the original number. Find the number.
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Step-by-step explanation:
let the tens digit number be 'a' and ones digit number be 'b'
a + b = 8 ( given ). - A
10a + b + 36 = 10b + a
9b - 9a = 36
b - a = 4 - B
by A + B we get
2b = 12
b = 6
a = 2
so the numbers are 26 and 62
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