Question

The sum of the digits of a two digit number is 8 . the number obtained by interchanging the digits exceeds the given number by 18. find given number .

Please answer fast​

Answer 1

Hence, the digits at ones place is 5. The digits at tens place = (8-5) = 3. So, the original number is 35 and the new number is 53.

Answer 2

Given:

• sum of two digit number = 8
• number obtained by interchanging the digits exceed the given number by 18

To Find:

the original number

Solution:

• the sum of 2 digit number is 8

Let the number at one's place be "x"

then,the digit at ten's place be (8 - x)

therefore,

original number = 10(8 - x) + x

$⟹$ 80 - 10x + x

$⟹$ 80 - 9x

on interchanging the digits from one's place to ten's place and vice versa

new number obtained = 10x + 8 - x

$⟹$ 9x + 8

According to question:

new number - original number = 18

$⟹$9x + 8 - (80 - 9x) = 18

$⟹$9x + 8 - 80 + 9x = 18

$⟹$18x - 72 = 18

$⟹$18x = 18 + 72

$⟹$18x = 90

$⟹$x = 90/18

$⟹$x = 5

So,

digit at one's place is 5

now, digit at ten's place = (8 - 5) = 3

Hence,

the original number is 35 and the number after interchanging the places of digits is 53