The sum of the digits of a two digit number is 8 . the ones digit is three times the ten digit. find the number.
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Step-by-step explanation:
To Find :-
The Number.
Solution :-
Let the unit place digit number be x.
And the tens place digit number be y.
According to the Question,
1st part,
x + y = 8 .... (ii)
2nd part,
x = 3y .... (i)
Putting x's value in Eq (ii), we get
⇒ x + y = 8
⇒ 3y + y = 8
⇒ 4y = 8
⇒ y = 8/4
⇒ y = 2
Putting y's value in Eq (ii), we get
⇒ x = 3y
⇒ x = 3 × 2
⇒ x = 6
Number = 26
Hence, the required number is 26.
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