the sum of the digits of a two digit number is 9 also nine times this number is twice the number obtained by reversing the order of the digits find the number
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Let the unit digit be x and tens digit be y.
So, the number will be = 10y + x
After interchanging the digits the number becomes = 10x + y
It is given that, The sum of the digits of two digit number is 9. Therefore we get :]
x + y = 9.......(Equation i)
It is also given that, Nine times this number is twice the number obtained by reversing the order of the digits :]
9(10y + x) = 2(10x + y)
90y + 9x = 20x + 2y
90y - 2y = 20x - 9x
188y = 11x
x = 8y.......(Equation ii)
____________________
Now,Putting the value of x = 8y in equation (i) we get :]
x + y = 9
8y + y = 9
9y = 9
y = 1
_____________________
Now, substitute the value of y in equation (ii) we get :]
x = 8y
x = 8(1)
x = 8
Therefore
- The original number will be 10y + x = 10(1) + 8 = 18
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